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$If A = [\begin{array}{cc} 2 & - 3 \\ - 4 & 1 \end{array}], then adj (3 A^{2} + 12 A) is equal to$

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51638472

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72−63−8451

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Correct option is B

We have __A=2−3−41∴A2=A⋅A=2−3−412−3−41=4+12−6−3−8−412+1=16−9−1213 Now, 3A2+12A=316−9−1213+122−3−41=48−27−3639+24−36−4812=72−63−8451∴ adj A2+12A=51638472

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If A=2−3−41, then adj⁡3A2+12A is equal to

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$If A = [\begin{array}{cc} 2 & - 3 \\ - 4 & 1 \end{array}], then adj (3 A^{2} + 12 A) is equal to$