If A=12-1-1122-11, then det. [adj (adj A)] is

We know that adj (adj A) = |A|n–2 A if |A| ≠ 0, provided order of A is n.∴ adj (adj A) = |A| A (as n = 3)∴ det [adj (adj A)] = |A|3 det A = |A|4.But A=12-1-1122-11=14∴ det [adj (adj A)] = (14)4.