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If , then det. [adj (adj A)] is
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a
(14)4
b
(14)3
c
(14)2
d
(14)1
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Correct option is A
We know that adj (adj A) = |A|n–2 A if |A| ≠ 0, provided order of A is n.∴ adj (adj A) = |A| A (as n = 3)∴ det [adj (adj A)] = |A|3 det A = |A|4.But A=12-1-1122-11=14∴ det [adj (adj A)] = (14)4.Similar Questions
Let be a square matrix of order such that , then equals
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