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Q.

If A=[221131122] , then A−1+(A−5I)(A−I2)=

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a

15[  4   2   −1−1   3       1−1   2      4]

b

15[  4   −2   −1−1       3   −1−1  −2      4]

c

13[  4    2   −1−1    3       1−1    2      4]

d

13[4   −2   −1−1      3    −1−1  −2      4]

answer is B.

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Detailed Solution

A−1+(A−5I)(A−I2)= 15[  4   −2   −1−1       3   −1−1  −2      4]
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If A=[221131122] , then A−1+(A−5I)(A−I2)=