If $$A=2012131$$−$$10$$, then $$A2$$−$$5A+6I$$ is equal to

Correct option is 11−1−3−1−1−10−544

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If $A = [\begin{array}{ccc} 2 & 0 & 1 \\ 2 & 1 & 3 \\ 1 & - 1 & 0 \end{array}]$ , then $A^{2} - 5 A + 6 I$ is equal to

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1−1−3−1−1−10−544

11−5−1−14−3−104

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detailed solution

Correct option is A

A2=2012131−102012131−10=5−129−250−1−2Now, A2−5A+6I=5−129−250−1−2−52012131−10+6100010001=5−10+6−1−0+02−5+09−10+0−2−5+65−15+00−5+0−1+5+0−2−0+6=1−1−3−1−1−10−544

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If A=2012131−10, then A2−5A+6I is equal to

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Ready to Test Your Skills?

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If $A = [\begin{array}{ccc} 2 & 0 & 1 \\ 2 & 1 & 3 \\ 1 & - 1 & 0 \end{array}]$ , then $A^{2} - 5 A + 6 I$ is equal to