If A3=0, then I+A+A2 equals
I−A
I+A1−1
I−A−1
none of these
Given A3=0
Now, (I−A)I+A+A2
=I2+IA+IA2−AI−A2−A3=I−A3=I⇒(I−A)−1=I+A+A2