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Q.

If A=2    2    11    3    11    2    2 then A−1+(A−5I)(A−I)2=

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a

154−2−1−13−1−1−24

b

15−42−1−13−1−124

c

421131124

d

15−4−211311−2−4

answer is A.

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Detailed Solution

(A−I)2=121121121121121121=484484484(A−5I)(A−I)2=−3211−2112−3484484484=000000000=0det⁡A=2(6−2)−2(2−1)+1(2−3)=8−2−1=5A−1=15( Adj A)=154−2−1−13−1−1−24
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