If a∈(−1,1) then roots of the quadratic equation (a−1)x2+ax+1−a2=0 are

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

real

imaginary

both equal

none of these

answer is A.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

(a−1)x2+ax+1−a2=0∴ D=a2−4(a−1)1−a2 =a2−4a1−a2+41−a2 a−21−a22+41−a21−1−a2>0 for a∈(−1,1) Hence roots are real but not equal.

Watch 3-min video & get full concept clarity