If a∈(−1,1) then roots of the quadratic equation (a−1)x2+ax+1−a2=0 are
real
imaginary
both equal
none of these
(a−1)x2+ax+1−a2=0∴ D=a2−4(a−1)1−a2 =a2−4a1−a2+41−a2 a−21−a22+41−a21−1−a2>0 for a∈(−1,1)
Hence roots are real but not equal.