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If $θ \in [\frac{π}{2}, \frac{3 π}{2}],$ then $\sin^{- 1} (\sin θ)$ equals

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Correct option is B

We have,θ∈π2,3π2⇒−θ∈−3π2,−π2⇒π−θ∈−π2,π2Also, sin⁡(π−θ)=sin⁡θ∴ sin−1⁡(sin⁡θ)=sin−1⁡(sin⁡(π−θ))=π−θ.

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If θ∈π2,3π2, then sin−1⁡(sin⁡θ) equals

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If $θ \in [\frac{π}{2}, \frac{3 π}{2}],$ then $\sin^{- 1} (\sin θ)$ equals