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 If A=123014221, then AT1=

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a
−98−5−87−4−22−1
b
−9−8−2872−5−4−1
c
10−2−2−12341
d
none

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detailed solution

Correct option is B

det A=1−1−8+20+8+30−2=−9+16−6=1A−1=AdjAdetA=AdjA=−98−5−87−4−22−1                                                =−9−8−2872−5−4−1                                    AT−1 =A−1T


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