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Questions  

If α,β,γ0,π2 then the value of sin(α+β+γ)sinα+sinβ+sinγ is

a
<1
b
>1
c
0
d
None of these

detailed solution

Correct option is A

sin⁡(α+β+γ)=sin⁡αcos⁡βcos⁡γ+cos⁡αsin⁡βcos⁡γ+cos⁡αcos⁡βsin⁡γ−sin⁡αsin⁡βsin⁡γ ⇒sin⁡(α+β+γ)−sin⁡α−sin⁡β−sin⁡γ =sin⁡α(cos⁡βcos⁡γ−1)+sin⁡β(cos⁡αcos⁡γ−1)+sin⁡γ(cos⁡αcos⁡β−1)−sin⁡αsin⁡βsin⁡γ ⇒ sin⁡(α+β+γ)−sin⁡α−sin⁡β−sin⁡γ<0⇒ sin⁡(α+β+γ)

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