If a2−4a+1=4,then the value of a3−a2+a−1a2−1a2≠1 is equal to____.
Given,a2−4a+1=4⇒a2+1=4(1+a)y=(a−1)1+a2a2−1=a2+1a+1=4(a+1)a+1=4