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Q.

If A=α22αand |A|3=125 then the value of α  is

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a

± 1

b

±2

c

±3

d

±5

answer is C.

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Detailed Solution

A=α22α    |A3|=|A|3=125 now  |A|=α2−4⇒(α2−4)3=125=53⇒α2−4=5⇒α=±3
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