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If 113+1517+19111+=π4, then value of 113+157+1911+is

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a
π8
b
π6
c
π4
d
π34

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detailed solution

Correct option is A

We have          π4=1−13+15−17+19−111+⋯            =21⋅3+25⋅7+29⋅11+⋯⇒       11⋅3+15⋅7+19⋅11+⋯=π8


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