If 1−13+15−17+19−111+⋯=π4, then value of 11⋅3+15⋅7+19⋅11+⋯is
π8
π6
π4
π34
We have π4=1−13+15−17+19−111+⋯ =21⋅3+25⋅7+29⋅11+⋯⇒ 11⋅3+15⋅7+19⋅11+⋯=π8