If α,β,γ∈0, π2then the value of sinα+β+γsinα+sinβ+sinγ is
>1
<1
=1
=0
We have sin(α+β)<sinα+sinβ for α,β∈ 0,π2⇒sin(α+β+γ)<sinα+sinβ+sinγ⇒sin(α+β+γ)sinα+sinβ+sinγ<1