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If $α = \frac{π}{14}$ then the value of $(\tan αtan 2 α + \tan 2 αtan 4 α + \tan 4 αtan α)$ is

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Correct option is A

α+2α+4α=7α=π2∴ tan⁡α⋅tan⁡2α+tan⁡2α⋅tan⁡4α+tan⁡α⋅tan⁡4α=1

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If α=π14 then the value of (tan⁡αtan⁡2α+tan⁡2αtan⁡4α+tan⁡4αtan⁡α) is

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If $α = \frac{π}{14}$ then the value of $(\tan αtan 2 α + \tan 2 αtan 4 α + \tan 4 αtan α)$ is