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 If A=3    3    42    3    40    1    1 , then the value of trace of the matrix adj adj A is 

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detailed solution

Correct option is A

Given matrix A=3−342−340−11|A|=3(−3+4)+3(2−0)+4(−2+0)=3+6−8=1 Now, adj (adj⁡(A))=|A|n−2A=1.A=A Trace of the matrix adj⁡( adj A)=3−3+1=1


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Let A be a square matrix of order 3 such that |Adj A|=100, then |A| equals 


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