First slide
Arithmetic progression
Question

If there are (2n + 1) terms in A.P., then the ratio of the  sum of odd terms and the sum of even terms is

Moderate
Solution

Let the A.P. containing (2n + 1) terms be
a, a + d, a + 2d, a + 3d, a + 4d, a + 5d, …, a + 2nd

The sum of odd terms of this A.P.

=a+(a+2d)+(a+4d)+ to (n+1) terms =n+12[2a+(n+11)×2d]=(n+1)(a+nd)

The sum of even terms of this A.P.

=(a+d)+(a+3d)+(a+5d)+ to n terms =n2[2(a+d)+(n1)×2d]=n(a+nd)

Hence, the required ratio = n+1n

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