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If three positive real numbers a, b, c are in A.P. such that abc = 4, then the minimum value of b is
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a
21/3
b
22/3
c
21/2
d
23/2
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Correct option is B
Since a,b, c are in A.P., therefore, b -a = d and c -b = d,where dis the common difference of the A.P.∴ a=b−d and c=b+dNow, abc=4⇒ (b−d)b(b+d)=4⇒ bb2−d2=4But, bb2−d2Similar Questions
If and 1 are in A.P, then x is equal to
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