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If 9 times the 9th term of an A.P is equal to 13 times the 13th term, then the 22nd term of the A.P is:

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a
0
b
22
c
220
d
198

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detailed solution

Correct option is A

9t9=13t139(a+8d)=13(a+12d)9a+72d=13a+13(12)d(−4a)=(156−72)d=84da=−21dt22=a+21d=0


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