First slide
Arithmetic progression
Question

If 9 times the 9th term of an A.P is equal to 13 times the 13th term, then the 22nd term of the A.P is:

Moderate
Solution

9t9=13t139(a+8d)=13(a+12d)9a+72d=13a+13(12)d(4a)=(15672)d=84da=21dt22=a+21d=0

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