If 9 times the 9th term of an A.P is equal to 13 times the 13th term, then the 22nd term of the A.P is:
0
22
220
198
9t9=13t139(a+8d)=13(a+12d)9a+72d=13a+13(12)d(−4a)=(156−72)d=84da=−21dt22=a+21d=0