First slide

Pair of straight lines

Question

If two equal sides of a triangle are $x^{2} + 4 x y + y^{2} = 0$ then locus of mid point of third side is

Moderate

A

$x y = 0$
B

$x^{2} + y^{2} - 4 x y = 0$
C

$x^{2} - 2 x y - y^{2} = 0$
D

$x^{2} - y^{2} = 0$

Solution

$a = 1, 2 h = 4, b = 1$
$h (x^{2} - y^{2}) = (a - b) x y$
$x^{2} - y^{2} = 0$

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