First slide
Theory of equations
Question

If the two equations x2-cx+d=0 and x2-ax+b=0 have common root and the second has equal roots, then 2(b+d)=

Moderate
Solution

Let roots of x2-cx+d=0 be α, β then roots of 

x2-ax+b=0 be α, α

 α+β=c, αβ=d, α+α=a, a2=b

Hence 2(b+d)=2(α2+αβ)=2α(α+β)=ac

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