If the two equations x2-cx+d=0 and x2-ax+b=0 have common root and the second has equal roots, then 2(b+d)=
0
a+c
ac
-ac
Let roots of x2-cx+d=0 be α, β then roots of
x2-ax+b=0 be α, α
∴ α+β=c, αβ=d, α+α=a, a2=b
Hence 2(b+d)=2(α2+αβ)=2α(α+β)=ac