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Questions  

If the two equations x2-cx+d=0 and x2-ax+b=0 have common root and the second has equal roots, then 2(b+d)=

a
0
b
a+c
c
ac
d
-ac

detailed solution

Correct option is C

Let roots of x2-cx+d=0 be α, β then roots of x2-ax+b=0 be α, α∴ α+β=c, αβ=d, α+α=a, a2=bHence 2(b+d)=2(α2+αβ)=2α(α+β)=ac

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