If two vertices of an equilateral triangle have integral coordinates then the third vertex will have
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a
coordinates which are irrational
b
atleast one coordinate which is irrational
c
coordinates which are rational
d
coordinates which are integers
answer is B.
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Detailed Solution
Let the vertices of the equilateral triangle be (x1, y1), (x2, y2) and (x3, y3). If none of xi and yi (i = 1, 2, 3) are irrational, then area of ∆=12x1y11x2y21x3y31=retionalBut the area of an equilateral triangle=34(side)2=irrationalThus, the two statements are contradictory. Therefore, both the coordinates of the third vertex cannot be rational.