If $$u=a1x+b1y+c1$$,$$v=a2x+b2y+c2=0$$ and $$a1a2=b1b2$$≠$$c1c2$$ then $$u+kv=0$$

Correct option is 2a family of parallel lines

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If $u = a_{1} x + b_{1} y + c_{1}, v = a_{2} x + b_{2} y + c_{2} = 0$ and $\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$ then $u + k v = 0$

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a family of concurrent lines

a family of parallel lines

u = 0 or v = 0

none of these

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detailed solution

Correct option is B

u = 0, v = 0 are parallel lines but not identical . u+kv=0 represents a family of lines parallel to these lines.

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If u=a1x+b1y+c1,v=a2x+b2y+c2=0 and a1a2=b1b2≠c1c2 then u+kv=0

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Ready to Test Your Skills?

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If $u = a_{1} x + b_{1} y + c_{1}, v = a_{2} x + b_{2} y + c_{2} = 0$ and $\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$ then $u + k v = 0$