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a
7
b
6
c
9
d
10
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Correct option is A
Given that 5+9+13+… upto n terms 7+9+11+…. upto (n+1) terms =1716 By the given condition n2[2.5+(n-1)4]n+12[2.7+(n+1-1)2]=1716⇒ nn+110+4n−414+2n=1716⇒n4n+6n+12n+14=1716⇒ n2n+3n+1n+7=1716⇒32n2+48n=17n2+136n+119⇒15n2−88n−119=0⇒ n−715n+17=0⇒n=7. ∵n=−1715 is not possibleSimilar Questions
If the sum of first terms of an is , then the sum of squares of these terms is
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