Questions
Remember concepts with our Masterclasses.
80k Users 60 mins Expert Faculty Ask Questions
a
32+π
b
23
c
32−π
d
23+π
Ready to Test Your Skills?
Check Your Performance Today with our Free Mock Tests used by Toppers!detailed solution
Correct option is B
Consider the integral I=∫012x21-x232dx Substitute x=sinθ,dx=cosθdθ and the limits are 0,π6 Hence, the given integral becomes I=∫0π6sin2θcos3θcosθdθ=∫0π6tan2θ dθ=∫0π6sec2θ−1 dθ=tanθ−θ0π6=13−π6 Therefore, k6+π=13-π6=6-3π63+π, it implies k=23Similar Questions
is equal to
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
Popular Books
HC Verma Part 1HC Verma Part 2RS AgarwalRD SharmaLakhmir SinghDK GoelSandeep GargTS GrewalNCERT solutions
Class 12 NCERT SolutionsClass 11 NCERT SolutionsClass 10 NCERT SolutionsClass 9 NCERT SolutionsClass 8 NCERT SolutionsClass 7 NCERT SolutionsClass 6 NCERT Solutions
