If the value of limx→0 (1−x)n−1x is 100 , then n=
100
-100
99
-99
We have,
limx→0 (1−x)n−1x=100=limx→0 (1−x)n−1n(1−x)−1=−100=n(1)n−1=−100⇒n=−100