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Questions  

If the value of the third term in the expansion of x+xlog10x5is 106  , then x may have value(s) 

a
1, 10
b
10,10−5/2
c
10,10−3/2
d
102,10−3/2

detailed solution

Correct option is B

T3=5C2x5−2xlog10⁡x2=106⇒x2log10⁡x+3=105⇒t(2t+3)=5 where t=log10⁡x⇒t=−5/2,1

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