If a variable takes values 0,1,2,…,n with frequencies 1,nC1,nC2,…,nCn then the AM is
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a
n
b
2nn
c
n+1
d
n2
answer is D.
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Detailed Solution
The required mean is given by X¯=0⋅1+1⋅nC1+2⋅nC2+3⋅nC3+…+n⋅nCn1+nC1+nC2+…+nCnX¯=∑r=0n r⋅nCr∑r=0n nCr=∑r=1n r⋅nrn−1Cr−1∑r=0n nCr=n∑r=1n n−1Cr−1∑r=0n nCrX¯=n×2n−12n=n2`