If vectors a→ and b→ are non-collinear, then a→|a→|+b→|b→| is

Obviously,  a→|a→|+b→|b→| is a vector in the plane of  a→ and b→ and hence perpendicular  to a→ × b→  It is  also equally inclined to  a→ and b→ as it is along the angle bisector.