If vectors A→=2i^+3j^+4k^,B→=i^+j^+5k^ and C→ form a left-handed system, then C→ is
11i^−6j^−k^
−11i^+6j^+k^
11i^−6j^+k^
−11i^+6j^−k^
For A→,B→ and C→ to form a left-handed system [A→B→C→]<0
A→×B→=i^j^k^234115=11i^−6j^−k^-----i
(i) is satisfied by options (2) and (4).