If the vertex of a hyperbola bisects the distance between its center and the corresponding focus, then the ratio of the square of its conjugate axis to the square of its transverse axis is
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a
2
b
4
c
6
d
3
answer is D.
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Detailed Solution
Let the hyperbola be x2a2−y2b2=1 Then, 2a=ae, i.e., e=2. Therefore, b2a2=e2−1=3 or (2b)2(2a)2=3