Questions

If the vertex of a hyperbola bisects the distance between its center and the corresponding focus, then the ratio of the square of its conjugate axis to the square of its transverse axis is

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detailed solution

Correct option is D

Let the hyperbola be x2a2−y2b2=1 Then, 2a=ae, i.e., e=2. Therefore, b2a2=e2−1=3 or (2b)2(2a)2=3

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