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If a vertex of a triangle is (1, 1) and the mid-points two sides through this vertex are ( - 1, 2) and ( 3, 2), then k centroid of the triangle, is

 

a
13,73
b
1,73
c
−13,73
d
−1,73

detailed solution

Correct option is B

Let ABC be the given triangle whose vertices areA(1,1),Bx1,y1 and Cx2,y2 Let D(−1,2) and E(3,2) be the mid-points of AB and AC respectively. Thenx1+12=−1,y1+12=2,x2+12=3 and y2+12=2⇒ x1=−3,y1=3,x2=5 and y2=3Thus the coordinates of the vertices of ∆ABC are A (1, 1). B(-3, 3) and C(5, 3).∴ _Coordinates of the centroid are 1−3+53,1+3+33=1,73

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