Questions
If the vertices of a triangle are and the area of triangle is , then the number of positive integral divisors of is
detailed solution
Correct option is B
The area of the triangle formed by the vertices A, B, C is 12AB¯×AC¯Here, AB¯=OB¯−OA¯=3i+4j−k−i−2j−3k=2i+2j−4kAC=OC−OA=5i−4j+2k−i−2j−3k=4i−6j−kHence, the area of the triangle is 12AB¯×AC¯=12ijk22−44−6−1=12i−2−24−j−2+16+k−12−8=12−26i−14j−20k=318 Consider , λ26+λ2+253=3186+318+253=53+3433=60=22⋅3⋅5 The number of integral divisors of the above number is 2+1⋅1+1⋅1+1=12Similar Questions
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests