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If the vertices of a triangle are $(\sqrt{5}, 0), (\sqrt{3}, \sqrt{2}), and (2, 1)$ , then the orthocenter of the triangle is

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(5,0)

(0,0)

(5+3+2,2+1)

None of these

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detailed solution

Correct option is C

The circumcenter of the triangle is (0,0) as vertices are at equal distance from (0,0). So, the orthocenter will be (sum of x-coordinates, sum of y-coordinates.)

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If the vertices of a triangle are (5,0),(3,2), and (2,1), then the orthocenter of the triangle is

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If the vertices of a triangle are $(\sqrt{5}, 0), (\sqrt{3}, \sqrt{2}), and (2, 1)$ , then the orthocenter of the triangle is