If the volume of the parallelepiped whose coterminous edges a¯=i^+j^+nk^, b¯= 2i^+4j^−nk^ and c¯=i^+nj^+3k^ (n≥0), is 158 cubic units then
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a
a¯.c¯=17
b
b¯.c¯=10
c
n=9
d
n=7
answer is B.
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Detailed Solution
Volume=a¯ b¯ c¯=11n24−n1n3=158⇒3n2-5n+6=158⇒3n2-5n+6=158 or 3n2-5n+6=-1583n2-5n-152=0 or 3n2-5n+164=0n=8 or n=-19/3. second equation has no real roots as ∆<0n=8 only since n≥0 so we get b¯⋅c¯=2+n=10