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If a and x are positive integers such that x<a and a-x, x, a+x are in A.P., then least possible value of a is

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a
5
b
7
c
11
d
none of these

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detailed solution

Correct option is A

We have 2x=a+x+a−x⇒       2x=2xa+x−a−x⇒a+x−a−x=xa+x+a-x-2a2-x2=x⇒2a-x=2a2-x2⇒4a2+x2-4ax=4a2-4x2⇒5x2=4ax∴       a=54xAs a and x are positive integers, least possible value of x is 4 and that of a is 5.


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