If x2+ax−3x−(a+2)=0 has real and distinct roots, then the minimum value of a2+1a2+2 is
1
0
1/2
1/4
D > 0
⇒ (a−3)2+4(a+2)>0
or a2−6a+9+4a+8>0
or a2−2a+17>0
⇒ a∈R∴ a2+1a2+2=1−1a2+2≥12