First slide
Introduction to Determinants
Question

If Δ=xabbxaabx, then a factor of  is

Moderate
Solution

Applying C1C1+C2+C3, we get

Δ=a+bxaba+bxxaa+bxbx=(a+bx)1ab1xa1bx=(a+bx)1ab0xaab0baxb                    [Applying R2R2R1 and R3R3R1]=(a+bx)(x+a)(x+b)+(ab)2                    [expanding along C1]=(a+bx)x2+(a+b)x+a2+b2ab

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