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If $Δ_{1} = |\begin{array}{lll} x b b \\ a x b \\ a a x \end{array}|$ and $Δ_{2} = |\begin{array}{ll} x b \\ a x \end{array}|$ then

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Δ1=3Δ22

ddxΔ1=3Δ2

ddxΔ1=3Δ22

Δ1=3Δ23/2

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detailed solution

Correct option is B

dΔ1dx=1 b b0 x b0 a x+x0ba1ba0x+x b 0a x 0a b 1=xbax+xbax+xbax=3Δ2

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If Δ1=x b ba x ba a x and Δ2=x ba x then

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Ready to Test Your Skills?

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If $Δ_{1} = |\begin{array}{lll} x b b \\ a x b \\ a a x \end{array}|$ and $Δ_{2} = |\begin{array}{ll} x b \\ a x \end{array}|$ then