If ax2+bx+10=0  does not have two distinct real roots, then the least value of 5a+b. is

lt is given that ax2+bx+10=0does not have two distinct real roots.∴ b2−40a≤0⇒a≥b240Let y=5a+b Then,y=5×b240+b=b2+8b8=18b2+8by=18(b+4)2−2≥−2Hence, the least value of 5a+b  is  -2.