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Q.

If a+x=b+y=c+z+1 , where a,b,c,x3,y,z are non-zero distinct real numbers, then xa+yx+ayb+yy+bzc+yz+c is equal to

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a

ya−c

b

0

c

ya−b

d

yb−a

answer is C.

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Detailed Solution

xa+yx+ayb+yy+bzc+yz+c=xa+yayb+ybzc+ycc3→c3-c1=xyayybzycC2→C2-C3=x+ayay+bybz+cycC1→C1+C3=y+byay+byby+b-1yc(∵ data )=00a-b10b-cy+b-1yc=(a-b)y
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