If x be real, then the maximum value of 5+4x-4x2 will be equal to
5
6
1
2
Let f(x)=5+4x-4x2=y⇒4x2-4x-5+y=0
Since x is real, so B2-4AC≥0
⇒16-4.4(-5+y)⩾0
⇒16-16(-5+y)⩾0⇒-5+y≤1⇒y≤6
Hence maximum value of y is 6.