Q.

If x be real, then the minimum value of x2-8x+17 is

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a

-1

b

0

c

1

d

2

answer is C.

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Detailed Solution

x2-8x+17=(x2-8x+16)+1=(x-4)2+1Since x is real, so (x-4)2 is always positive and its least value is 0 and so the minimum value of given expression is 1.
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