If x=c is a root of order 2 of a polynomial f(x), then x=c is also a root of the polynomial
f′(x)
f′′(x)
f′′′(x)
none of these
Since x = c is a root of order 2 of the polynomial f(x)
∴ f(x)=(x−c)2ϕ(x)
⇒f′(x)=2(x−c)ϕ(x)+(x−c)2ϕ′(x)
⇒f′(c)=0⇒x=c is a roots of f′(x)