If ax2+cy+a′x2+c′=0 and x is a rational function of y and ac is negative, then
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a
ac′+a′c=0
b
aa′=cc′
c
a2+c2=a′2+c′2
d
aa′+cc′=1
answer is B.
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Detailed Solution
Wehave: ax2+cy+a′x2+c′=0 or x2ay+a′+cy+c′=0. If x is rational, then the discriminant of the above equation must be a perfect square. i.e. 0−4ay+a′cy+c′ must be a perfect square i.e. −acy2−ac′+a′cy−a′c=0 [∵ Disc. =0] ----(1)⇒ ac′+a′c2−4aca′c′=0 we get perfect square when roots are equal and roots are equal if discriminant of (1) is zero⇒ ac′−a′c2=0⇒ac′=a′c⇒aa′=cc′