If x→+c→×y→=a→ and y→+c→×x→=b→ where c→ is a non-zero vector ,then which of the following is not correct?
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a
x→=b→×c→+a→+(c→⋅a→)c→1+c→⋅c→
b
x→=c→×b→+b→+(c→⋅a→)c→1+c→⋅c→
c
y→=a→×c→+b→+(c→⋅b→)c→1+c→⋅c→
d
none of these
answer is C.
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Detailed Solution
x→+c→×y→=a→-----iy→+c→×x→=b→----iiTaking cross with c→ , we have c→×y→+c→×(c→×x→)=c→×b→⇒ (a→−x→)+(c→⋅x→)c→−(c→⋅c→)x→=c→×b→ Also x→+c→×y→=a→⇒ c→⋅x→+c→⋅(c→×y→)=c→⋅a→ or c→⋅x→+0=c→⋅a→ or c→⋅x→=c→⋅a→⇒ a→−x→+(c→⋅a→)c→−(c→⋅c→)x→=c→×b→ or x→(1+(c→⋅c→))=b→×c→+a→+(c→⋅a→)⋅c→ or x→=b→×c→+a→+(c→⋅a→)c→1+c→⋅c→Similarly on taking cross product of Eq. (i), we findy→=a→×c→+b→+(c→⋅b→)c→1+c→⋅c→