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If $x \cos â¡ Î¸ = y \cos â¡ (Î¸ + 2 Ï / 3) = z \cos â¡ (Î¸ + 4 Ï / 3)$ then $x y + y z + z x =$

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Correct option is D

K1x+1y+1z=cosâ¡Î¸+cosâ¡(Î¸+2Ï/3)+cosâ¡(Î¸+4Ï/3) =cosâ¡Î¸+2cosâ¡(Î¸+Ï)cosâ¡Ï/3=cosâ¡Î¸âcosâ¡Î¸=0â xy+yz+zx=0

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If xcosâ¡Î¸=ycosâ¡(Î¸+2Ï/3)=zcosâ¡(Î¸+4Ï/3) then xy+yz+zx=

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If $x \cos â¡ Î¸ = y \cos â¡ (Î¸ + 2 Ï / 3) = z \cos â¡ (Î¸ + 4 Ï / 3)$ then $x y + y z + z x =$