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If $x = \cos e c^{2} θ : y = \sec^{2} θ, z = \frac{1}{1 - \sin^{2} θ \cos^{2} θ}$ they $x y z =$

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Correct option is A

We have x=cosec2θ, y=sec2θ and z=11-sin2θcos2θ Now z=11-sin2θcos2θ =11-1x1y =xyxy-1 ⇒zxy-1=xy ⇒xyz=xy+z →1 Also xy=cosec2θsec2θ =1sin2θcos2θ =sin2θ+cos2θsin2θcos2θ =1sin2θ+1cos2θ =x+y →2 By 1 and 2, we have xyz=xy+z=x+y+z

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If x=cosec2θ : y=sec2θ , z =11−sin2θcos2θ they xyz =

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If $x = \cos e c^{2} θ : y = \sec^{2} θ, z = \frac{1}{1 - \sin^{2} θ \cos^{2} θ}$ they $x y z =$