If x=cosec2θ : y=sec2θ , z =11−sin2θcos2θ they xyz =
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a
x+y+z
b
xy+z
c
x+y−z
d
x+yz
answer is A.
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Detailed Solution
We have x=cosec2θ, y=sec2θ and z=11-sin2θcos2θ Now z=11-sin2θcos2θ =11-1x1y =xyxy-1 ⇒zxy-1=xy ⇒xyz=xy+z →1 Also xy=cosec2θsec2θ =1sin2θcos2θ =sin2θ+cos2θsin2θcos2θ =1sin2θ+1cos2θ =x+y →2 By 1 and 2, we have xyz=xy+z=x+y+z