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If $x = a (\cos θ + θ \sin θ), y = a (\sin θ - θ \cos θ)$ then $a θ =$

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x+y−a

x2+y2−a2

x2−y2+a2

x−y+a

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detailed solution

Correct option is B

x2+y2=a2cos2⁡θ+sin2⁡θ+θ2sin2⁡θ+θ2cos2⁡θ=a21+θ2⇒aθ=x2+y2−a2

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If x=a(cos⁡θ+θsin⁡θ),y=a(sin⁡θ−θcos⁡θ) then aθ=

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If $x = a (\cos θ + θ \sin θ), y = a (\sin θ - θ \cos θ)$ then $a θ =$