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Questions  

If xcosθ=ycosθ2π3=zcosθ+2π3, then x+y+z=

a
1
b
0
c
-1
d
2

detailed solution

Correct option is B

We have,xcos⁡θ=ycos⁡θ−2π3=zcos⁡θ+2π3Therefore, each ratio is equal to    x+y+zcos⁡θ+cos⁡θ−23π+cos⁡θ+2π3=x+y+z0⇒    x+y+z=0

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